Source: https://leetcode.com/problems/reverse-linked-list/

Given the head of a singly linked list, reverse the list, and return the reversed list.

/**
* Definition for singly-linked list.
* function ListNode(val, next) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
*/
/**
* @param {ListNode} head
* @return {ListNode}
*/
// O(N) time, O(1) space
var reverseList = function(head) {
let previous = null;
let current = head;
// Loop through all nodes in the linked list
while (current !== null) {
// Store the current node's next pointer to move onto after we reversed the current node
const nextTemp = current.next;
// Change current node's next pointer to point to its previous node
current.next = previous;
// Update the previous node with the current node we flipped
previous = current;
// Advance current node to the next node in the original list
current = nextTemp;
}
// New head reference should be in previous at the end
return previous;
};